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[api] Namespace view a file API

Romain Rigaux 4 years ago
parent
commit
7523e04157

+ 1 - 1
desktop/core/src/desktop/api_public.py

@@ -129,7 +129,7 @@ def autocomplete(request, server=None, database=None, table=None, column=None, n
 
 
 @api_view(["GET"])
-def view(request, path):
+def storage_view(request, path):
   django_request = get_django_request(request)
   return filebrowser_views.view(django_request, path)
 

+ 1 - 1
desktop/core/src/desktop/api_public_urls.py

@@ -75,7 +75,7 @@ urlpatterns += [
 ]
 
 urlpatterns += [
-  re_path(r'^storage/view=(?P<path>.*)$', api_public.view, name='api_storage_view'),
+  re_path(r'^storage/view=(?P<path>.*)$', api_public.storage_view, name='api_storage_view'),
   re_path(r'^storage/download=(?P<path>.*)$', api_public.storage_download, name='api_storage_download'),
 ]