Prakash Ranade d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
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LICENSE d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
MANIFEST.in d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
Makefile d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
PKG-INFO d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
README d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
README.md d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
ipaddress.py d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
setup.cfg d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
setup.py d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve
test_ipaddress.py d51d6fb821 HUE-3287 [core] Django 1.11 upgrade 7 éve

README

ipaddress
=========

Python 3.3+'s [ipaddress](http://docs.python.org/dev/library/ipaddress) for Python 2.6, 2.7, 3.2.

Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:

```python
>>> from __future__ import unicode_literals
>>> ipaddress.ip_address('1.2.3.4')
IPv4Address(u'1.2.3.4')
```
or
```python
>>> ipaddress.ip_address(u'1.2.3.4')
IPv4Address(u'1.2.3.4')
```
but not:
```python
>>> ipaddress.ip_address(b'1.2.3.4')
Traceback (most recent call last):
File "", line 1, in
File "ipaddress.py", line 163, in ip_address
' a unicode object?' % address)
ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?
```